Integrand size = 28, antiderivative size = 127 \[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=-\frac {2 (1-2 x)^{3/2} \sqrt {2+3 x}}{15 (3+5 x)^{3/2}}-\frac {18 \sqrt {1-2 x} \sqrt {2+3 x}}{25 \sqrt {3+5 x}}+\frac {38}{125} \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )+\frac {212 \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{125 \sqrt {33}} \]
38/375*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)+212/ 4125*EllipticF(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-2/15*( 1-2*x)^(3/2)*(2+3*x)^(1/2)/(3+5*x)^(3/2)-18/25*(1-2*x)^(1/2)*(2+3*x)^(1/2) /(3+5*x)^(1/2)
Result contains complex when optimal does not.
Time = 6.18 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.73 \[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=\frac {2 \left (-\frac {55 \sqrt {1-2 x} \sqrt {2+3 x} (86+125 x)}{(3+5 x)^{3/2}}-209 i \sqrt {33} E\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right )|-\frac {2}{33}\right )+315 i \sqrt {33} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right ),-\frac {2}{33}\right )\right )}{4125} \]
(2*((-55*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*(86 + 125*x))/(3 + 5*x)^(3/2) - (209* I)*Sqrt[33]*EllipticE[I*ArcSinh[Sqrt[9 + 15*x]], -2/33] + (315*I)*Sqrt[33] *EllipticF[I*ArcSinh[Sqrt[9 + 15*x]], -2/33]))/4125
Time = 0.22 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.08, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {108, 27, 167, 176, 123, 129}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {(1-2 x)^{3/2} \sqrt {3 x+2}}{(5 x+3)^{5/2}} \, dx\) |
| \(\Big \downarrow \) 108 |
| \(\displaystyle \frac {2}{15} \int -\frac {3 \sqrt {1-2 x} (8 x+3)}{2 \sqrt {3 x+2} (5 x+3)^{3/2}}dx-\frac {2 (1-2 x)^{3/2} \sqrt {3 x+2}}{15 (5 x+3)^{3/2}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {1}{5} \int \frac {\sqrt {1-2 x} (8 x+3)}{\sqrt {3 x+2} (5 x+3)^{3/2}}dx-\frac {2 \sqrt {3 x+2} (1-2 x)^{3/2}}{15 (5 x+3)^{3/2}}\) |
| \(\Big \downarrow \) 167 |
| \(\displaystyle \frac {1}{5} \left (-\frac {2}{5} \int \frac {19 x+22}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {18 \sqrt {1-2 x} \sqrt {3 x+2}}{5 \sqrt {5 x+3}}\right )-\frac {2 (1-2 x)^{3/2} \sqrt {3 x+2}}{15 (5 x+3)^{3/2}}\) |
| \(\Big \downarrow \) 176 |
| \(\displaystyle \frac {1}{5} \left (-\frac {2}{5} \left (\frac {53}{5} \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx+\frac {19}{5} \int \frac {\sqrt {5 x+3}}{\sqrt {1-2 x} \sqrt {3 x+2}}dx\right )-\frac {18 \sqrt {1-2 x} \sqrt {3 x+2}}{5 \sqrt {5 x+3}}\right )-\frac {2 (1-2 x)^{3/2} \sqrt {3 x+2}}{15 (5 x+3)^{3/2}}\) |
| \(\Big \downarrow \) 123 |
| \(\displaystyle \frac {1}{5} \left (-\frac {2}{5} \left (\frac {53}{5} \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {19}{5} \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )-\frac {18 \sqrt {1-2 x} \sqrt {3 x+2}}{5 \sqrt {5 x+3}}\right )-\frac {2 (1-2 x)^{3/2} \sqrt {3 x+2}}{15 (5 x+3)^{3/2}}\) |
| \(\Big \downarrow \) 129 |
| \(\displaystyle \frac {1}{5} \left (-\frac {2}{5} \left (-\frac {106 \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{5 \sqrt {33}}-\frac {19}{5} \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )-\frac {18 \sqrt {1-2 x} \sqrt {3 x+2}}{5 \sqrt {5 x+3}}\right )-\frac {2 (1-2 x)^{3/2} \sqrt {3 x+2}}{15 (5 x+3)^{3/2}}\) |
(-2*(1 - 2*x)^(3/2)*Sqrt[2 + 3*x])/(15*(3 + 5*x)^(3/2)) + ((-18*Sqrt[1 - 2 *x]*Sqrt[2 + 3*x])/(5*Sqrt[3 + 5*x]) - (2*((-19*Sqrt[11/3]*EllipticE[ArcSi n[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/5 - (106*EllipticF[ArcSin[Sqrt[3/7]*Sq rt[1 - 2*x]], 35/33])/(5*Sqrt[33])))/5)/5
3.28.49.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^p/(b*(m + 1))) , x] - Simp[1/(b*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f* x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c , d, e, f}, x] && LtQ[m, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2 *n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])
Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_ )]), x_] :> Simp[(2/b)*Rt[-(b*e - a*f)/d, 2]*EllipticE[ArcSin[Sqrt[a + b*x] /Rt[-(b*c - a*d)/d, 2]], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] && !L tQ[-(b*c - a*d)/d, 0] && !(SimplerQ[c + d*x, a + b*x] && GtQ[-d/(b*c - a*d ), 0] && GtQ[d/(d*e - c*f), 0] && !LtQ[(b*c - a*d)/b, 0])
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x _)]), x_] :> Simp[2*(Rt[-b/d, 2]/(b*Sqrt[(b*e - a*f)/b]))*EllipticF[ArcSin[ Sqrt[a + b*x]/(Rt[-b/d, 2]*Sqrt[(b*c - a*d)/b])], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ [(b*e - a*f)/b, 0] && PosQ[-b/d] && !(SimplerQ[c + d*x, a + b*x] && GtQ[(d *e - c*f)/d, 0] && GtQ[-d/b, 0]) && !(SimplerQ[c + d*x, a + b*x] && GtQ[(( -b)*e + a*f)/f, 0] && GtQ[-f/b, 0]) && !(SimplerQ[e + f*x, a + b*x] && GtQ [((-d)*e + c*f)/f, 0] && GtQ[((-b)*e + a*f)/f, 0] && (PosQ[-f/d] || PosQ[-f /b]))
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] - Simp[1/(b*(b*e - a*f)*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b* c*(f*g - e*h)*(m + 1) + (b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h )*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]
Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]* Sqrt[(e_) + (f_.)*(x_)]), x_] :> Simp[h/f Int[Sqrt[e + f*x]/(Sqrt[a + b*x ]*Sqrt[c + d*x]), x], x] + Simp[(f*g - e*h)/f Int[1/(Sqrt[a + b*x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && Sim plerQ[a + b*x, e + f*x] && SimplerQ[c + d*x, e + f*x]
Leaf count of result is larger than twice the leaf count of optimal. \(218\) vs. \(2(93)=186\).
Time = 1.35 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.72
| method | result | size |
| default | \(\frac {2 \left (135 \sqrt {5}\, \sqrt {7}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-95 \sqrt {5}\, \sqrt {7}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}+81 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )-57 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )-3750 x^{3}-3205 x^{2}+820 x +860\right ) \sqrt {1-2 x}\, \sqrt {2+3 x}}{375 \left (6 x^{2}+x -2\right ) \left (3+5 x \right )^{\frac {3}{2}}}\) | \(219\) |
| elliptic | \(\frac {\sqrt {-\left (-1+2 x \right ) \left (3+5 x \right ) \left (2+3 x \right )}\, \left (-\frac {2 \left (-30 x^{2}-5 x +10\right )}{15 \sqrt {\left (x +\frac {3}{5}\right ) \left (-30 x^{2}-5 x +10\right )}}-\frac {88 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{2625 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}-\frac {76 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, \left (-\frac {7 E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{6}+\frac {F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{2}\right )}{2625 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}-\frac {22 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}{1875 \left (x +\frac {3}{5}\right )^{2}}\right )}{\sqrt {1-2 x}\, \sqrt {2+3 x}\, \sqrt {3+5 x}}\) | \(219\) |
2/375*(135*5^(1/2)*7^(1/2)*EllipticF((10+15*x)^(1/2),1/35*70^(1/2))*x*(2+3 *x)^(1/2)*(1-2*x)^(1/2)*(-3-5*x)^(1/2)-95*5^(1/2)*7^(1/2)*EllipticE((10+15 *x)^(1/2),1/35*70^(1/2))*x*(2+3*x)^(1/2)*(1-2*x)^(1/2)*(-3-5*x)^(1/2)+81*5 ^(1/2)*(2+3*x)^(1/2)*7^(1/2)*(1-2*x)^(1/2)*(-3-5*x)^(1/2)*EllipticF((10+15 *x)^(1/2),1/35*70^(1/2))-57*5^(1/2)*(2+3*x)^(1/2)*7^(1/2)*(1-2*x)^(1/2)*(- 3-5*x)^(1/2)*EllipticE((10+15*x)^(1/2),1/35*70^(1/2))-3750*x^3-3205*x^2+82 0*x+860)*(1-2*x)^(1/2)*(2+3*x)^(1/2)/(6*x^2+x-2)/(3+5*x)^(3/2)
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.69 \[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=-\frac {450 \, {\left (125 \, x + 86\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1} - 1543 \, \sqrt {-30} {\left (25 \, x^{2} + 30 \, x + 9\right )} {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right ) + 1710 \, \sqrt {-30} {\left (25 \, x^{2} + 30 \, x + 9\right )} {\rm weierstrassZeta}\left (\frac {1159}{675}, \frac {38998}{91125}, {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right )\right )}{16875 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} \]
-1/16875*(450*(125*x + 86)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1) - 15 43*sqrt(-30)*(25*x^2 + 30*x + 9)*weierstrassPInverse(1159/675, 38998/91125 , x + 23/90) + 1710*sqrt(-30)*(25*x^2 + 30*x + 9)*weierstrassZeta(1159/675 , 38998/91125, weierstrassPInverse(1159/675, 38998/91125, x + 23/90)))/(25 *x^2 + 30*x + 9)
\[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=\int \frac {\left (1 - 2 x\right )^{\frac {3}{2}} \sqrt {3 x + 2}}{\left (5 x + 3\right )^{\frac {5}{2}}}\, dx \]
\[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=\int { \frac {\sqrt {3 \, x + 2} {\left (-2 \, x + 1\right )}^{\frac {3}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}}} \,d x } \]
\[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=\int { \frac {\sqrt {3 \, x + 2} {\left (-2 \, x + 1\right )}^{\frac {3}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {(1-2 x)^{3/2} \sqrt {2+3 x}}{(3+5 x)^{5/2}} \, dx=\int \frac {{\left (1-2\,x\right )}^{3/2}\,\sqrt {3\,x+2}}{{\left (5\,x+3\right )}^{5/2}} \,d x \]